2r^2+4R-48=0

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Solution for 2r^2+4R-48=0 equation:


Simplifying
2r2 + 4R + -48 = 0

Reorder the terms:
-48 + 4R + 2r2 = 0

Solving
-48 + 4R + 2r2 = 0

Solving for variable 'R'.

Move all terms containing R to the left, all other terms to the right.

Add '48' to each side of the equation.
-48 + 4R + 48 + 2r2 = 0 + 48

Reorder the terms:
-48 + 48 + 4R + 2r2 = 0 + 48

Combine like terms: -48 + 48 = 0
0 + 4R + 2r2 = 0 + 48
4R + 2r2 = 0 + 48

Combine like terms: 0 + 48 = 48
4R + 2r2 = 48

Add '-2r2' to each side of the equation.
4R + 2r2 + -2r2 = 48 + -2r2

Combine like terms: 2r2 + -2r2 = 0
4R + 0 = 48 + -2r2
4R = 48 + -2r2

Divide each side by '4'.
R = 12 + -0.5r2

Simplifying
R = 12 + -0.5r2

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